Question
Determine the area between the two concentric circles whose equations are $(x-2)^{2}+(y+4)^{2}=16$ and $(x-2)^{2}+$ $(y+4)^{2}=64$. Concentric circles are circles that have the same center.
Step 1
The first circle has equation $(x-2)^2+(y+4)^2=16$, which means its radius is $\sqrt{16}=4$. The second circle has equation $(x-2)^2+(y+4)^2=64$, which means its radius is $\sqrt{64}=8$. Show more…
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