00:01
To determine the bond angles found in all of these molecules, we will first draw the lewis structure.
00:07
For the first one, we have nh4 plus.
00:11
So we'll put nitrogen in the middle and the four hydrogen surrounding it.
00:14
Nitrogen has four valence, five valence electrons.
00:18
There's one valence electron for each hydrogen, so that's plus another four.
00:22
And then because it's positively charged, one of the valence electrons has been removed.
00:26
So that's a total of eight valence electrons, which gives us, say, tetrahedral molecular geometry or a bond angle at 109 .5 degrees.
00:36
For the next one we have s -o -3 -2 -minus so we'll put a sulfur in the middle and the three oxygen surrounding it.
00:46
Sulfur has six.
00:48
There are three oxygens also with six valence electrons but this has a two minus charge so there's two additional valence electrons for a total of 26.
00:57
You plug in all 26 and and we end up with extra loan pair that we can put on the sulfur, resulting in a tetrahedral electron, electronic geometry, and a trigonal pyramidal molecular geometry.
01:18
So the bond angle is going to be just under 109 .5.
01:23
Then we go to the next one, we have n -o -2, n -2 minus...