00:01
So when the switch a is closed, all the charges is going through a capacitor 1.
00:07
Because when switch a is closed, only capacitor 1 exists in the circuits.
00:14
So therefore, we'll have the maximum amount of charge is just simply equal to the capacitance c1 times delta v.
00:24
Dlv is the potential difference across the battery, which is the potential difference across the circuits.
00:29
And windows c1 is equal to 15 microbarra and delta v is 100 volts.
00:36
So therefore, we have the maximum amount of charge is equal to 1 ,500 microcolon.
00:42
So now we switch the position.
00:46
So now switch b is close.
00:49
So once switch b is closed, the total amount of charges will start redistributing.
00:55
So therefore, since it's a parallel circuit, okay? so we have a maximum amount of charge should be equal to q1 plus q2.
01:05
Q1 is the amount of charge at capacitor 1, and q2 is the amount of charge at capacitor 2.
01:12
And q2 should be equal to q3, and q3 here is the amount of charge at capacitor 3.
01:17
It's because c2 and c3 are connected in series.
01:22
So we also know that the potential difference across capacitor 1 should be equal to the total of the potential difference at capacity 2 and the potential difference across capacitor 3, which is v1 is equal to v2 plus v3.
01:42
And we know potential difference, v1 here can be equal to q1 over c1, and v2 here can be able to q2 over c2, and v3 here can be equal to q3 over c3.
01:54
Because remember, potential can be able to charge over capacitance.
02:02
So therefore, we'll have q1 over c1.
02:05
Is also equal to q2 over c2 plus q2 over c3.
02:09
Because remember, q2 is equal to q3...