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Determine the concentration of a $\mathrm{NH}_{4}…

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Problem 97 Medium Difficulty

Determine the concentration of a $\mathrm{NaNO}_{2}$ solution that has a pH of 8.22.

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Video Transcript

for this problem. We're going to do another calculation working with salts and were given the following information. The salt that we're looking at is sodium nitrate, and it has a pH of 8.22 Now, when I look at this, I can see that this the basic solution. So I'm going to be interested in my o h concentration. Let me write my equation the night, right? An eye on is gonna be an equilibrium with nitrous acid. And this there's a water over on this side. But I'm just gonna add it sort of as an aside, because it's a liquid not gonna impact what I'm doing. Okay, so there's my chemical equation, and we're going to prepare an ice table and then do our calculations. Okay, here's what we need to look at First, I need to get the concentration using my pH. And I want a concentration of the O age. In order to do that, I've got to use my ph to get toe. Ohh. I'm gonna take 14 minus 8.22 equals, I believe that was 5.25 point seven hit. Where did it right this 5.78 That equals my p o age. Now, for my concentration for my, um, equilibrium concentration, which is given here, I know that that is gonna be derived from this number. I'm gonna find that as follows. I'll put a little start on here. I'm gonna take that negative. I'm gonna take 10 to the negative. 5.78 when I do that, tend to the negative. 5.78 I got 1.66 times 10 to the negative sixth. And these are the values. I'm gonna put these in red. So my this is 1.66 times 10 to the minus six. This is 1.66 times 10 to the minus six. The change was plus and plus 1.66 and 1.66 times 10 to the minus six zero and zero. Here's what I don't know on this problem I'm solving for this X. So my change here is going to be pop negative. This had to go down 1.66 times 10 to the minus six, and that's going to give me for this value X minus 1.66 times 10 to the minus six. Okay, I'm gonna write these three values down on our next page. Our equilibrium concentrations for N O to minus. It was X minus 1.66 times 10 to the minus six. And for my c H three wrong substance. What am I thinking? H and 02 it was 1.66 times 10 to the minus six is similarities. And last but not least, for the old H, It was also 1.66 times 10 to the minus six. Okay, now we could look up. We're gonna look up r k B for that and on to K B for n 02 minus is an extremely low number is 2.2 times 10 to the minus 11th. Let's consider this for a moment. Um, I'm gonna write r k b expression R k B expression will be r N o to minus on the bottom on the denominator and the keep ready. Wanting to write acetic acid up there. Nitrous acid and the hydroxide ion inter numerator. Okay, so for this value, which we have listed as X minus 1.66 times 10 to the minus six. Just a sui have ignored this part when we've had to subtract something when it's been a minus. X. When we have an extremely low number here, we can ignore this right now, and this will be approximately equal to X. So we're just going to use X and our denominator. Let's plug in our values 2.2 times, 10 to the minus 11 equals. And then these two values air the same sorts 1.66 times, 10 to the minus six squared over acts. So for X and I got to two decimal places, 0.13 and we need 0.13 because my given pH it will think back all right, in a very light color was 8.22 which means I can have two significant figures. I can have as many significant figures in my concentration as I have decimal places in my Ph. And that is malaria T. Thanks for listening

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Determine the concentration of a $\mathrm{NH}_{4}…

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Watch More Solved Questions in Chapter 15

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Raymond Chang, Kenneth A. Goldsby

Chemistry

Theodore Donnell

Stephen Pulliam

Karli Sipps

Jake Rempel

This textbook answer is only visible when subscribed! Please subscribe to view the answer

Chemistry

Theodore Donnell

Stephen Pulliam

Karli Sipps

Jake Rempel

Raymond Chang, Kenneth A. GoldsbyChemistry

Theodore Donnell

Stephen Pulliam

Karli Sipps

Jake Rempel

Raymond Chang, Kenneth A. Goldsby

Chemistry