00:01
Hello, and today we will be solving a problem which states that determine the current flowing in the rl circuit if the applied emf is et is equal to e0 sine omega -t, where e -0 and omega are constant.
00:14
And then they're asking us to identify the transient part of the solution and the steady -stay solution.
00:19
So the first thing to do is that we're going to write our differential equation for the rl circuit.
00:26
That is just i prime plus r over l times i that's all equal to et over l we know that the et just equal to e0 sine omega t so what we're doing is we're going to plug that in into our differential equation so the next thing to do is that we're going to take e to the integral of our coefficient next to i, which is r l, respect to d t.
01:24
And then what we'll get is e to the rl, r over l times t.
01:33
So what we can do, we're gonna multiply that to our original equation.
01:45
What we'll get is e r over l times t.
01:59
We'll multiply by i prime plus r over l times e to the, r over l times t power i multiply by i that's equal to one over l multiplied by e zero sine t sine of omega t times e to the r over l times t power so we know that the left side of the differential equation that is just the antiderative of e to the r over l times t, i multiply by i...