00:01
In this question we're going to apply kirchhoff's rules for circuit analysis to determine the current in each branch of the circuit shown.
00:10
So our first thing to do is set up our two loops.
00:13
I'm going to start at the 12 volt battery and go counterclockwise around the outside loop.
00:20
I'm going to call this loop one with current one directed upward in that branch.
00:27
And then my second loop is going to start at the 4 volt battery and go counterclockwise around the left half of this circuit.
00:40
And we're going to call i2 directed upward in that branch.
00:44
And then of course at the junction at the top, above the 5 ohm resistor pictured and to the left of the 3 ohm resistor pictured is where we're going to have current i3 emerging when we had i2 entering from the bottom and i1 entering from the right.
01:11
So that gives our three rules to loop one junction.
01:16
So now we can go ahead and set up our first loop.
01:28
So remember kirchhoff's rules are basically, well the loop rules are conservation of energy.
01:32
So we're going to have a 12 volt potential rise and then we'll have i1 times 1 ohm as a potential drop.
01:40
And then we'll have i1 times 3 ohms as a potential drop.
01:45
And then we will have i3 times 8 ohms as a potential drop.
01:50
And then we're back to the battery so that's a total of zero.
01:52
So simplifying this we get 12 minus 4 i1 minus 8 i3 equals zero.
02:02
So rearranging this one so that the currents are on one side and the constant term for the battery is on the other.
02:13
4 i1 plus 8 i3 equals 12.
02:16
Now we can do the same thing for our second loop where we started with the 4 volt battery.
02:22
And then we will have i2 times 1 ohm as a potential drop.
02:29
And we will have i2 times 5 ohms as a potential drop.
02:33
And then we will have i3 times 8 ohms as a potential drop.
02:38
And then we are back to the battery so that equals a total of zero.
02:42
Sum of potential rises equals sum of potential falls.
02:46
And the rises minus falls equals zero.
02:49
So again simplifying this we get 4 minus 6 i2 minus 8 i3 equals zero...