We can use the parallel axis theorem to do this. The moment of inertia about the X axis, $I_x$, is given by $I_x = \frac{1}{36} a^2 b^3 + \frac{1}{2} a b^2 d^2$, where $a$ is the base of the triangle, $b$ is the height of the triangle, and $d$ is the distance from
Show more…