University of New Mexico

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Problem 47

Determine the empirical formulas of the compounds with the following compositions by mass:

$$

\begin{array}{l}{\text { (a) } 10.4 \% \mathrm{C}, 27.8 \% \mathrm{S}, \text { and } 61.7 \% \mathrm{Cl}} \\ {\text { (b) } 21.7 \% \mathrm{C}, 9.6 \% \mathrm{O}, \text { and } 68.7 \% \mathrm{F}} \\ {\text { (c) } 32.79 \% \mathrm{Na}, 13.02 \% \mathrm{Al}, \text { and the remainder } \mathrm{F}}\end{array}

$$

Answer

a) See explanation for solution.

b) Empirical Formula - C3OF6

c) see explanation

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## Discussion

## Video Transcript

First of all, we need to calculate the number off moles off each element just to remind you the formula for a number of moves is equal to be it often particular. Cambone, divided by more legal moss, more muss. So, using this formula, the number off move off, carbon sinful and chlorine are being too. Don't as for to deter mined the smallest ball number issue by dividing each mold by 0.86 fine made doing that. We have carbon as one cell for his one and chlorine as toe for the we can ride the empirical formula as C s seal two for auction be We need to calculate the number off moles off each element, using the same formula as weight divided by the molecule a Mars. The number of moves for carbon oxygen and Florian are being determined to determine the empirical formula. V divide this smallest ball number racial with 0.6 eagle giving us carbon has 3.1 oxygen as one while flooring as sticks. For though we confined the empirical formula as C three F six oh, next to calculate the number off moles off each element using the same formula as we eat. Divided by the molecule moss, we have a number off moves off sodium aluminum on Floren, respectively, to determine the smallest ball number ratio by dividing each mole by zero point 48 to five. We have sodium almost equally well in 23 aluminum as one and flooring equivalent to six. We can write the empirical formula else sodium. Three aluminium on chlorine six.

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