00:01
So in this problem, in the figure, there are six different registers combined in different ways.
00:07
So i'm labeling them r1, r2, r3, r4, r5, and r6.
00:13
Your choice, whether you want to label r1 as r2 or r3 or whatever, you just choose the way you want.
00:20
So we want to find the resistance across a and b, which is rab.
00:27
So start with where you can simplify it.
00:30
Actually i see that r1 and r2 are in series with each other and r3 and r4 are in parallel with each other.
00:40
So i'm going to start with that.
00:42
So i'm going to find r12 equals r1 plus r2 which is going to be 4 plus 6 om.
00:54
It is 10 om, right? similarly r3 4 equals r3 parallel r4 and this is going to be equal to r3 times r4 over r3 plus r4 and this is going to give me 4 .24 oh now i'm going to simplify the circuit instead of writing these two race source i'm going to write down r34 and simply similarly for r1 and r2, i'm going to write down r12.
01:32
So let's do that.
01:34
Next page.
01:36
So the next page is going to look like this.
01:42
This is r34, and this is r6, and this is r12.
02:00
And this to are point a and b.
02:04
Okay, so r12, r34, r5, and r6.
02:14
So that's the simplified circuit now.
02:17
Now you can see that r34 and r12 are in parallel with each other.
02:22
So let's find that out...