Question
Determine the exact values of the six trigonometric functions of the angle $\boldsymbol{\theta}$.A.B.
Step 1
For part A, the point is given as $(-\sqrt{3}, -1)$, so $x = -\sqrt{3}$ and $y = -1$. Therefore, $r = \sqrt{x^2 + y^2} = \sqrt{(-\sqrt{3})^2 + (-1)^2} = \sqrt{3 + 1} = 2$. Show more…
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