00:01
These ideal gas law calculations are basic algebra calculations, so long as you know how to rearrange the ideal gas law to solve for the single variable.
00:12
Rearrangement of the ideal gas law to solve for volume gives us nrt over p is equal to v.
00:20
So n is given to us as 1 .5 moles.
00:24
R is 0 .08206, liter atmospheres per kelvin mole.
00:31
And then the temperature is going to be negative 6 celsius plus the 273 to get our absolute kelvin temperature.
00:39
We then divide that by the pressure.
00:42
The pressure needs to be in atmospheres because we're using this as our r value with units of liter atmospheres per kelvin mole.
00:50
And the pressure was given to us as 1 .25 atmospheres.
00:56
This then gives us a 26 .3 liter volume.
01:00
The next gas, for the next gas we're solving for 10.
01:03
So rearrangement of this gives us pv over nr is equal to t.
01:09
The pressure needs to be in atmospheres.
01:12
So if we have 250 tor, we need to divide by 760 to get it in atmospheres.
01:17
We'll then multiply that by the volume.
01:21
The volume is given to us as 478 milliliters, which can easily be converted to 0 .478 liters...