00:01
In this problem, we're going to ask to look at this trust here, but now we want to figure out the forces in these two members here.
00:11
So we're going to make a cut like this, just like we did last time, but just shifted down one section.
00:17
And again, we'll be able to figure out what these are, but we won't be able to figure out the absolute value of these two forces in these two members, but we'll be able to figure out what the difference is.
00:29
So we make the cut and we expose our forces in this horizontal member and the two forces in the vertical member.
00:36
So we actually again have four unknowns, but we're only going to have three equations.
00:42
Some in the forces in the x direction, in the y direction, and then the moments about this point here to give us our three equations.
00:52
And again, we can see that fhi and fhg always occur in fhi.
00:59
Always occur as a difference okay so here there's a difference here there's a difference we could change this around a little bit to make it think more a little more explicit we could say let's see this is like this a minus sign and then this a minus and then this a plus so we have hg hg fhi minus fhg as a basically an unknown here...