00:01
Okay, now to start this or finding the general solution to this equation, we're first going to solve or find the corresponding solution of the homogeneous equation.
00:14
So first let's write this in operator form like so.
00:20
So then y is equal to 5e to the 2x.
00:25
Actually, write that in black.
00:29
So this is the original equation here.
00:31
Now, the corresponding homogeneous equation is when this equation we have is equal to 0.
00:39
And we're going to solve this is the complementary solution here.
00:44
So let's see, we can factor this as well.
00:49
So this is going to become d minus 2, d plus 1 like so.
00:57
And then yc is equal to 0.
00:59
So this has a corresponding auxiliary equation, r minus 2.
01:04
And then r plus 1 like so, that's equal to 0, equals 0.
01:11
So we get r is equal to 2 and negative 1.
01:14
All right.
01:15
Now, therefore, our complementary solution, y, c of x, is going to take the form c1e to the 2x plus c2e to the negative x.
01:28
Now, we need to take care of our right -hand side here.
01:32
So that is f of x is equal to 5e to the 2x.
01:38
So then our annihilator, if we see here we have an r is equal to 2.
01:43
So our annihilator, a of d is going to be d minus r.
01:49
So d minus, and then here we have d minus, d minus 2.
01:58
Now we're going to, sorry, we're going to multiply, or apply our operator to both sides of this equation here.
02:08
So we can do it like d minus 2.
02:13
And then we also have d minus 2, d plus 1, y is equal to 0...