00:01
Okay, so to find the general solution to this equation here, we're first going to find the complementary solution.
00:07
So that's going to be y complement plus what complement prime is equal to zero like this.
00:13
So if we write this in differential operator form, that's going to be d squared plus 1, y complement is equal to 0.
00:20
So this has the corresponding auxiliary equation p of r is equal to r squared plus 1 is equal to 0.
00:31
So then r is going to, or r squared is equal negative 1, so r is equal to plus or minus i here.
00:40
So then our complementary solution is going to be of the form c1, sign of x, plus c2 cosine of x.
00:53
Now for the right hand side here, we have f of x is equal to 6e to the x.
01:00
So we need to find a corresponding annihilator.
01:03
So here we have r is equal to 1.
01:08
So the annihilator is going to be d minus r.
01:12
So d minus 1 like so.
01:15
So applying the annihilator to our, well, we can apply it to this here.
01:21
So we have d minus 1 and then d squared plus 1 like so.
01:28
Y is equal to 0.
01:30
So remember the annihilator turns this into 0...