The formula for the polar moment of inertia for a solid circular shaft is given by:
\[
J = \frac{\pi d^4}{32}
\]
where \(d\) is the diameter of the shaft. Given that the diameter \(d = 8 \, \text{in}\):
\[
J = \frac{\pi (8)^4}{32} = \frac{\pi \times 4096}{32} =
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