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Determine the infinite limit.

$ \displaystyle \lim_{x \to 2^+}\frac{x^2 - 2x -8}{x^2 -5x +6} $

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03:48

Daniel Jaimes

Calculus 1 / AB

Chapter 2

Limits and Derivatives

Section 2

The Limit of a Function

Limits

Derivatives

Oregon State University

Harvey Mudd College

Boston College

Lectures

04:40

In mathematics, the limit of a function is the value that the function gets very close to as the input approaches some value. Thus, it is referred to as the function value or output value.

In mathematics, a derivative is a measure of how a function changes as its input changes. Loosely speaking, a derivative can be thought of as how much one quantity is changing in response to changes in some other quantity; for example, the derivative of the position of a moving object with respect to time is the object's velocity. The concept of a derivative developed as a way to measure the steepness of a curve; the concept was ultimately generalized and now "derivative" is often used to refer to the relationship between two variables, independent and dependent, and to various related notions, such as the differential.

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in this problem, we want to find a limit of this expression as X approaches to from the positive side, it's going to be an infinite limit. So that means this expression is either going to approach positive infinity or negative infinity. As X approaches to from the positive side. Uh And the way we're going to ah approach this problem is we are going to factor uh the numerator and the denominator of this rational expression. So x squared minus two x minus eight will factor into x minus four Times X-plus two And then the denominator will factor into X -3 Times X -2. Now, as X approaches to from the positive side, x minus four will approach to -4 or negative too, X plus two will approach for as X approaches to from the positive side, As X is approaching two, X-plus two will be approaching for the x minus three factor in the denominator as X approaches to from the positive side. Well, as X is approaching two to minus three negative one, X minus three will approach negative one as X approaches to from the positive side. So these three factors all approach uh an actual number as X approaches to from the positive side. Uh this factor Um this X -2 factor, this is the one we need to look at closely, What does this X -2 factor approach as X approaches to from the positive side? Well, if x is approaching two from the positive side, that means we're getting near to but we're always a little bit higher than to like, you know, 2.42 point 32.22 point 12 point oh 12.1. We keep getting closer to two but from the positive side always a little bit above two. So if X is approaching two from the positive side, the closer you get to two from the positive side, X -2 is going to be a tiny positive number. Okay, so this gets closer and closer to zero. Okay, this approaches zero are from you know, the positive site. So as x approaches to from the positive side, X -2 is going to be a very small positive number. Give you a little example. I suppose X is approaching two from the positive side, we're really close to two from the positive side. Like 2.001 Then 2.001 -2 is .001. So .001 um is A positive number. .001 is positive but it's really close to zero. So it's a really tiny positive number. Now when you take a really tiny positive number um and times by a negative one. Ok, these two together the x minus three times x minus two as x is approaching two from the positive side X -2 is getting close to zero tiny number but it's still positive but this x minus tree factor was approaching negative one. So this might be 0.1 but this is close to negative one. So negative one times 10.1 is a negative 0.1. So the whole denominator as X approaches to from the positive side okay approaches zero but is negative. So a negative tiny number. So the whole denominator, the x minus three times X minus two approaches zero and it's negative. Okay, so think of a negative tiny number Like -201. Now we already know uh that the whole numerator um the whole numerator is approaching uh negative two times four, which is a positive eight. I'm sorry, a negative eight. So the whole numerator approaches -8. So ultimately as X approaches to from the positive side, the numerator approaches -8. And the denominator uh becomes a tinier and tinier negative number. Well, first of all, a negative eight divided by a tiny negative number. Just the fact that it's a negative tiny number, A negative divided by a negative is going to be positive. So we know the limit is going to you know, be approaching a positive amount. No uh negative eight divided by a tiny negative number. When you take a number like eight and divided by a tiny number. For example eight divided by point oh one. There's going to be 800 Eight divided by a tinier number. Like .0001 is going to be an even larger number 80,000. So negative eight over a tiny negative number. As the tiny negative number gets even tinier, uh This entire limit is going to approach positive infinity. So the limit of dysfunction as X approaches to from the positive side is positive infinity. Last but not least, I wanted to show you graphically what this function looks like and to support the answer that we found for our limit. Um you can see that as X approaches to from the positive side, this function is heading towards positive infinity.

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