Question
Determine the lattice constant of $\mathrm{NaCl}$ crystal. The molecular weight of $\mathrm{NaCl}$ is $58.44$ and the density is $2.167 \mathrm{~g} \mathrm{~cm}^{-3}$.
Step 1
44 g/mol ÷ (6.02214076×10^23 mol^−1) = 3.884×10^−22 g. Show more…
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PROBLEMS 1.1 Determine the lattice constant of NaCl crystal. The molecular weight of NaCl is 58.44 and the density is 2.167 g cm-3
Calculate the lattice constant of NaCl crystal using weight of NaCl = 58.45, density of NaCl = 2170 kg/m^3, Avogadro's number = 6.023 * 10^23.
Formula mass of $\mathrm{NaCl}$ is $58.45 \mathrm{~g} \mathrm{~mol}^{-1}$ and density of its pure form is $2.167 \mathrm{~g} \mathrm{~cm}^{-3}$. The average distance between adjacent sodium and chloride ions in the crystal is $2.814 \times 10^{-8} \mathrm{~cm} .$ Calculate Avogadro constant.
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