00:02
From the gravitational force law, we know that the force between two massive objects is equal to the universal gravitational constant g.
00:12
And in this case, the masses of the two objects are capital m, the mass of the earth, times little m, the mass of the moon, over the separation between m squared, r squared.
00:25
And we also know that this force, the normal force that acts between the object, results.
00:35
In centripetal motion.
00:38
So from newton's second law, fn is equal to m -a -n the normal component of the acceleration, which is m v squared over r.
00:53
So v squared is the tangential acceleration and r is a separation between the two planets or between the earth and the moon.
01:01
So we can now equate these two forces.
01:06
So what this means is that g capital m little m over r squared is equal to little m v squared over r.
01:26
Remember little m is the mass of the moon.
01:29
So in short we have the earth with mass m and it has a radius big r and the separation between the earth and the moon is little r.
01:53
So if we look at this equation, the small ms cancel on either side, and we get that the mass of the earth, capital m, is equal to r over g times v squared.
02:10
And if we assume that this orbit of the moon is circular about the earth, then the velocity at which the earth, the moon orbits the earth, is equal to its circumference, two -pireth...