00:02
All right, in this problem, we've been once again asked to determine the mass percent of various constituent elements in a larger compound.
00:11
So for this problem, the compound we're working with is apparently a fungicide, copper 2 oleate, which is c .u .c.
00:24
18, h.
00:32
33, and o sub 2.
00:38
And we're trying to determine the mass percent of not one specific element in this compound, but every element in this compound.
00:46
So it's kind of like, you know, every specific element.
00:48
So the first step we're going to do is we're going to add up how many of each element we have present in this compound.
00:54
So we're going to start with copper, and we have one copper.
00:58
And for carbon, we have 36 carbons, it's 18 times 2.
01:05
For hydrogen, we have 33 times 2, which is 66.
01:09
And for oxygen that's an o that's an o bear with me we have four oxygens so now what we're going to do is because we want this in terms of mass we're going to multiply each of these by the atomic weights which is 63 .55 grams per mole this is 12 .01 this is 1 .01 this is 1 .01 this is 16 .0 .0 and these are all in grams per mole.
01:49
So when we multiply these out, we get 63 .555 grams per mole.
02:03
We get 432 .36 grams per mole.
02:13
We get hydrogen is 66 .66 grams per mole.
02:21
And for oxygen we get 64.
02:25
Grams per mole.
02:27
And now this is the total weight per mole, the total weight in grams per mole of each unit of compound, of each element present in that compound.
02:38
So this is going to be useful.
02:39
This is one key part in determining the answer to the solution.
02:42
But the other part we need is the total weight of the molecule, which we're going to get by adding up or summing via the sigma notation here...