00:01
Problem number 8, the t of 1 -0 -0 -0 and 0 is equal to 2 -0 -0 -0 minus 1 -0 -0 -0 and 0, which is equal to 1 -0 -0 and 0.
00:30
Similarly, 0 -0 -1 and 0 is equal to 0 -0 -2 -0 minus 0, 0, 0, and 0, which is equal to 0, negative 1, 2, and 0.
00:54
T of 01, 0 and 0 is equal to 02, 0 and 0 minus 0, 0, 0, 0, 0, 0, is equal to 0 negative 1 and 0.
01:16
T of 0 and 0, 0 and 1 is equal to 0 and 0, 0, 0 and 2, minus minus.
01:30
0 and 0, 0 and 1, which is equal to 0 and 0, 0 and 1.
01:41
We have to show that these t is can be written as a linear combination of vector from c.
01:50
So, t of e1 and 1 is equal to 1, 0, 0, and 0, is equal to 1 times e1 plus 0 times e1 plus 0 times e2, plus 0 times e2.
02:17
The t of e1 and 2 is equal to 0 and negative 1, 2, 2 and 0, 2, 2 and 2.
02:27
Is equal to 0 multiplied by e11 plus 2 multiplied by a12 plus negative 1, multiplied by e2 1 plus 0 multiplied by a2 2.
02:49
For the of e2 1, this is 1 2 and this is 2 1, which is equal to 0 and 2, which is equal 0 and 2, 0, which is equal 0, 2, 2...