00:01
In this problem we are asked to find the maximum, let's say this is an inductor, we are asked to find the maximum flux, maximum magnetic flux.
00:14
So i will write a b for magnetic flux.
00:18
Maximum antics flux through this inductor.
00:20
We can write from the definition of a flux that in magnetic flux is given by a number of turns, a cross -sectional area times a b.
00:29
So we'll find a b and substitute the value and they get the maximum main flux through the inductor.
00:36
We can find a b by writing equation for xl first, that is, reactance is equal to 2 pi f times l, where we know that irms is equal to vr -rms divided by xl reactants.
00:55
So if we substitute the value for xl, that is 2 pi, fl here and our i max is i max is equal to square root of two times i rmsm if we substitute the value for i if you write r rm s in terms of i max we can get this is this will be square root of two vrmss divided by 2 pi fl then um we know the magnet field inside the inductor that that is b is equal to mu number of turns times the current passing through inductor maximum divided by l.
01:43
L is the length of the wire or inductor.
01:47
From here, then we can simplify this to mu n times square root of 2 times vr -rms.
01:56
We substituted the value for ir max that we found previously, divided by 2, fl divided by l.
02:07
Our v -no -l will be equal to u -not n squared by times a divided by l.
02:17
So we'll substitute the value for l for an inductor.
02:21
So substituting the value for l, that is, we get here relation for a b will be equal to square root of a 2, mu -nodd n, vrms, divided by 2 pi f, f, times mu nod n square a divided by l times l...