Question
Determine the maximum shearing stress in a solid shaft of 1.4-in. diameter as it transmits 66 hp at a speed of $(a) 750 \mathrm{rpm}$ (b) 1500 rpm.
Step 1
We know that Power (P) = Torque (T) × Angular speed (ω) First, we need to convert the power from hp to ft-lb/s. We know that 1 hp = 550 ft-lb/s. So, 66 hp = 66 × 550 = 36300 ft-lb/s Now, we need to calculate the angular speed (ω) in rad/s. We know that ω = 2π Show more…
Show all steps
Your feedback will help us improve your experience
Anand Jangid and 60 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Determine the maximum shearing stress in a solid shaft of $12-\mathrm{mm}$ diameter as it transmits $2.5 \mathrm{kW}$ at a frequency of $(a) 25 \mathrm{Hz},(b) 50 \mathrm{Hz}$
A hollow steel drive shaft $\left(G=11.2 \times 10^{6} \mathrm{psi}\right)$ is $8 \mathrm{ft}$ long and its outer and inner diameters are respectively equal to 2.50 in. and 1.25 in. Knowing that the shaft transmits 200 hp while rotating at 1500 rpm, determine $(a)$ the maximum shearing stress, $(b)$ the angle of twist of the shaft.
The shaft is supported by a smooth thrust bearing at $A$ and a smooth journal bearing at $B$. If the shaft is made from a material having an allowable shear stress of $\tau_{\text {allow }}=75 \mathrm{MPa}$, determine the maximum value for $P$.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD