00:01
In this problem, you need to show how these two reagents react and decide whether it's an s -n -1 mechanism or an s -n -2 mechanism.
00:09
In the products, you have to show specific stereochemistry if it exists.
00:13
So the first step we need to take is to identify what kind of halide it is.
00:19
So this is a primary halide, meaning that it's only going to react by an s -n -2 mechanism.
00:24
This is also a strong nucleophile, but since its primary alkylide, it's going to react.
00:30
By an s &2 anyway.
00:33
So it attacks in a concerted step, attacking the carbon and kicking out the leaving group in the same step.
00:39
And our product is this.
00:45
If this were a stereo center, it would invert the stereo chemistry, but it's not, so we don't have to worry about that in part a.
00:54
In part b, our reagents are that in the a's ion.
01:14
So once again, you identify what kind of alphalate it is.
01:18
And this is secondary so it can do s in one or s and two so then you look at the nucleophile and it's a strong nucleophile so instead of favoring s in one it favors s and two so once again it attacks in a concerted concerted fashion attacking and kicking out the leaving group in the same step and s and two reactions invert the stereo chemistry where it was attacked so you get this product and just make sure to pay attention to the stereocchemistry there.
01:58
And c, our reagents are this and this.
02:16
So once again you identify what kind of aqua halide it is.
02:18
This one is tertiary, so it can only react via an s in one mechanism...