Problem

Determine the molarity of each of the following s…

05:49

Problem 47 Hard Difficulty

Determine the molarity for each of the following solutions:
(a) 0.444 $\mathrm{mol}$ of $\mathrm{CoCl}_{2}$ in 0.654 $\mathrm{L}$ of solution
(b) 98.0 $\mathrm{g}$ of phosphoric acid, $\mathrm{H}_{3} \mathrm{PO}_{4},$ in 1.00 $\mathrm{L}$ of solution
(c) 0.2074 g of calcium hydroxide, $\mathrm{Ca}(\mathrm{OH})_{2},$ in 40.00 $\mathrm{mL}$ of solution
(d) 10.5 $\mathrm{kg}$ of $\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}$ in 18.60 $\mathrm{L}$ of solution
(e) $7.0 \times 10^{-3}$ mol of $\mathrm{I}_{2}$ in 100.0 $\mathrm{mL}$ of solution
(f) $1.8 \times 10^{4} \mathrm{mg}$ of $\mathrm{HCl}$ in 0.075 $\mathrm{L}$ of solution

Answer

(a) 0.679$M$
(b) 1.00 $\mathrm{M}$
(c) 0.06998 $\mathrm{M}$
(d) 1.75 $\mathrm{M}$
(e) 0.070 $\mathrm{M}$
(f) 6.6 $\mathrm{M}$

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Chemistry 102

Chemistry 101

Chemistry

Chapter 3

Composition of Substances and Solutions

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Video Transcript

this question. We've been actually Copley, the minority of each of the following solutions. So in order to Coakley, the polarity is important to note exactly what the melodious to the polarity of a solution is given by the moon to ready by the volume. So for each of these solutions, we just need to find out what the Moelis and divide by the bowling. So for the first question, this is relatively easy because we've been given both quantities, the more we've been given this 0.4 44 well, we just have to divide this by the bowling with a solution, which is my given as zero point 654 leaders to this thin results in similarity off their point 679 Moeller. That's similarity of a solution. We could do the same thing for Part B, but important be we have to now calculate the mole because we only being given the mass. So, like I stated previously, the morality yes, going by the more divided by the volume and for the more that is given by the massed divided by the molar Mass. So given the masters of the masses, 98.0, Gramps, you can divide this by the moon and Mars off. Let's wreak acid. And the mill Imus A calculated was 97 point 994 grams per more. So that would give us the mall. You're the numerator in this for Miller and I would previously more patrolling. Now all we have to do is divide this quantity. But they've only which is 1.0 leaders. This one sold should give a value approximately 1.0 zero Moeller. So current forward for part C. We're going to do the same thing as we differ. Pride be because I've been given a mass and we have to calculate the we're already here. So the polarity, like I stated, which I'm going to just represented by Capital M for part C, it is The mole is the moon of William, right? So the move is the mass directed by the more mass here the mass has been given, which is 7.2074 gramps. But we want the more for the numerator like we've been doing in past examples. So we derided by the molar mass of causing my drug side, the mullahs most of calcium hydroxide when I calculated that was 74.92 So it's still only 4.0 92 This obviously asked units grams per more. We couldn't divide this by the volume the volunteers for the familiars. We can cover that two leaders because it's the polarity issues that given units off more per liter. So 40 millimeters is this, um zero. All right, well, looks like I can write that underneath there, but 40 milliliters iss Well, go ahead by zero point zero for zero leaders. So this would result in a concentration wolf. Sorry. Yeah, concentration. Which is the polarity off zero point zero 69 nine eight cooler. So we just do similar thing for part D. E and F here. I'm just going to speed up a little bit. So for party the polarity, which I'm gonna just indicated by m here, I couldn't give him by, like, I've been doing more prevalent. And the move here have been given the mass. We have to find the mole a mass. So the masses one, there's 10 point five kilograms to cover that two grams. That's just turns into the part three grams. We divide this by the well, a mass for sodium sulfite deca hydrate that Mullah must went calculated. I go to Valley off 3 to 2.186 three, right, and I was just divide by the bowling. The ruling be given his 18.6 leaders. It's when sold. This gives the value 1.75 more in Part E. This is really simple because we've been given, the more I have been given the volume but head of loneliness and familiars yourself to cover that's leaders. The melody is the moon just 7.0 times tens of the poor, minus three? No whether by volume, 100 milliliters, sis 3.1 leaders. So this essentially uses of early a zero point They're 70 Moeller. And lastly, 1.8 times since of the bar four mainly graham off each seal in 0.75 liters of solution. So one point, sometimes a powerful milligram is 18 grams. Right? So, um, polarity we're going to be 18 grams. Do right by the mullahs. Mask off. Easier because we need to calculate the malls. The movements of a Chino is 36 point for 58 Graham Spoon, you divide this by the volume just zero point 075 leaders who insult this gives us the value off 6.5 neat war. I always feel this is how you Coakley similarity when given you the mass or the mole and the volume as well.

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