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Determine the molarity of each of the following solutions:(a) 1.457 mol $\mathrm{KCl}$ in 1.500 $\mathrm{L}$ of solution(b) 0.515 $\mathrm{g}$ of $\mathrm{H}_{2} \mathrm{SO}_{4}$ in 1.00 $\mathrm{L}$ of solution(c) 20.54 g of $\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}$ in 1575 mL of solution(d) 2.76 $\mathrm{kg}$ of $\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}$ in 1.45 $\mathrm{L}$ of solution(e) 0.005653 $\mathrm{mol}$ of $\mathrm{Br}_{2}$ in 10.00 $\mathrm{mL}$ of solution(f) 0.000889 $\mathrm{g}$ of glycine, $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NO}_{2},$ in 1.05 $\mathrm{mL}$ of solution

(a) 0.9713$M$(b) $5.25 \times 10^{-3} \mathrm{M}$(c) 0.6123 $\mathrm{M}$(d) 0.594$M$(e) 0.5653$M$(f) 0.0113$M$

Chemistry 102

Chemistry 101

Chapter 3

Composition of Substances and Solutions

Solutions

Composition

Rice University

University of Toronto

Lectures

03:07

A liquid is a nearly incom…

04:38

A liquid is a state of mat…

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What is the molarity of ea…

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Calculate the molarity of …

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Determine the molarity for…

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morality is calculated as moles divided by leaders. And so if we have 1.457 moles of K C L in 1.5 liters of solution Yeah. Okay. Armel Arat, ease 0.9 seven. If we have 0.515 g of H two s 04 we first have to convert that two moles and the molar mass of H two s 04 is 98.78 grams and we get 0.5 moles. If that's in one leader of solution, that gives us one. I'm sorry. Point 005 Mueller, If we have 20.54 g a l and 03 three convert that to moles. First using the Mueller maths and the molar mass of that is to 12.994 and you get point 10 Mole, once you're a mole divided by 1.575 leaders. Yeah, equals Why 06 Mohler, If we have two point 0.5653 moles of B R. Two in 10 mL of solution. You have to convert that toe leaders So 10 divided by 1000 gives us 0.1 leaders. Did you get 0.5653? But by a 0.1 leaders, That gives us 0.56 53 Mueller.

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