We can write the equilibrium constant expression for this reaction as follows:
\[K_{P}=\frac{P_{Ar^{+}}P_{e^{-}}}{P_{Ar}}\]
where $P_{Ar^{+}}$, $P_{e^{-}}$, and $P_{Ar}$ are the partial pressures of $\mathrm{Ar}^{+}$, $e^{-}$, and $\mathrm{Ar}$, respectively.
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