00:01
In this question, you have to determine what is the moment of inertia of this shaded area when it's rotating about the x -axis.
00:09
So this area will rotate about this axis.
00:14
Okay, keep that in mind.
00:16
Now, in order to evaluate the moment of inertia, you have to use this equation.
00:21
And this equation tells us that the moment of inertia is equal to the integral of y squared element of area.
00:28
So all we have to do in this kind of question is determine what is the expression for the element of area.
00:35
To do that, it's nice to begin by drawing what would be an element of area in this situation.
00:41
And there are two possibilities.
00:43
We can draw a horizontal element of area, which would be something like that.
00:48
Or we could draw a vertical element of area, which would be something like that.
00:53
So in order to decide if you are using a horizontal element of area or a horizontal element of area, vertical element of area, you have to take a look here at the expression for the moment of inertia.
01:04
In this expression, the variable is y.
01:07
So you would like to have something that has a dy in it.
01:13
And what have a dy in it? this version of the element of area or this version? well, it happens to be this version, because in this version, you have dy and then you have the x coordinate.
01:28
Expression for the element of area is the following.
01:31
Da is equals to x, d .y.
01:34
And that's it.
01:35
So let me raise the other element of area, which will be something like y, d .x, and we are not interested in that situation and continue serving the equation from here.
01:46
Okay, it would be very nice to draw that element of area in the figure so that you can have a better visualization of the situation.
01:53
So let me draw it.
01:55
So an element of area would be something like this.
02:01
Okay, and this would be red.
02:04
So let me paint it red in order to be more clear about what i'm saying.
02:10
Okay, so what are the measures of this element of area? as you can see, you have a height here and that height is the y and you have a width right here and that width as you can guess is just x.
02:25
So the moment of inertia is given by the integral of y square and d -a, which happens to be x, d -y.
02:35
So now you have two variables.
02:36
How can you get rid of one of those two variables? it happens that you have two choices.
02:42
You can solve this equation for x and then substitute that expression for x here, or you can just plug in y squared here and then work with an interval over x.
02:56
You can do whatever you want.
02:58
You have these two choices.
03:00
Go with serving this equation for x and then plug in here.
03:04
So solving that equation for x is nothing outside of this word...