The differential element has a height of $y_2 - y_1$, where $y_2 = \frac{b}{\sqrt{a}}x^{1/2}$ and $y_1 = \frac{b}{a^2}x^2$. Therefore, the area of the differential element $dA$ is given by
\[dA = (y_2 - y_1)dx = \left(\frac{b}{\sqrt{a}}x^{1/2} -
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