determine-the-number-of-moles-of-solute-in-each-of-these-aqueous-solutions-a-50-mathrml-of-010-mat-2

Question

Determine the number of moles of solute in each of these aqueous solutions.
a. 50 $\mathrm{L}$ of 0.10 $\mathrm{MaCl}$
b. 0.25 $\mathrm{L}$ of 3.0 $\mathrm{MC}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$
c. 35 $\mathrm{mL}$ of 12.0 $\mathrm{MCl}$
d. 300 $\mathrm{mL}$ of 0.025 $\mathrm{M} \mathrm{NaOH}$

David Collins · Accepted Answer

question Number eight were asked to determine the total number of moles of solute that includes all the ions that air present once we add the salute to the solvent. For the first one, we have 50 leaders of 500.1 Moeller sodium chloride. So if we take the volume and we multiply it by the molar ity, we will get the moles of sodium chloride. But sodium chloride being a strong electrolyte, completely dissociates into two moles of ions, one sodium and one chloride. So we end up with two moles of solute for every one mole of sodium chloride. So we get 10 moles of total salute for the next one. We have a 10.25 leader solution, that is three. Moeller will multiply the two together in order to get the moles of C six h 12 06 Then we&#x27;ll recognize that glucose is a non electrolyte. It does not dissociate into anything, so one mole of it produces just one mole salute. So we get 10.75 Mol salute. Then, if we have 35 mil leaders of 12 Moeller HCL, we&#x27;ll first convert the mill leaders two leaders, then multiply it by the molar ITI in order to get our moles of H. C l and recognize that HCL is a strong acid, a strong electrolyte that will completely disassociate into H plus and C L minus. So we get two moles of solute for every one mole HCL or 10.84 Moles of solute in the 35 mil leaders. If we then have 300 mL of 0 to 5 Mueller sodium hydroxide, we&#x27;ll first convert the mill leaders, two leaders and then the leaders two moles of sodium hydroxide and then recognize sodium hydroxide is a strong electrolyte that completely dissociates, and we get one sodium ion and one hydroxide ion or two moles salute for every one mole sodium hydroxide, so we get 15 most of total salute in 300 mL.

Nadia Lara · Answer

recall that polarity is represents molds for everyone. Leader. So we&#x27;re gonna treat polarity as a conversion factor. And because we&#x27;re dealing in leaders, I first have to fix this milliliters divide by 1000 to find that this is equal to 0.350 leaders. Once I have that finally multiple, simple matter of multiplying the number of leaders by the polarity. But instead of writing a polarity as Moeller, I&#x27;m gonna write it as 1.200 moans for everyone. Leader solution, which is definition of malaria. When I multiply these together, I find that this is equal to zero point near a 420 moles Salyut, in this case of value is each other same approach in part B. I&#x27;m gonna treat the polarity as a conversion factor that smalls For every leader, I need the leaders in units, milliliters and units of leaders. So I&#x27;m gonna divide by 1000 and find that I&#x27;m working with 10000.175 leaders multiplying by the polarity. That&#x27;s 0.67 moles in everyone. Leader notice of these leaders cancel, which is how we find most of Salyut. This is equal to zero point one to most of glucose, and I used to significant figures because the 0.67 only had two significant.

Freddie Montague · Answer

So for this question, we are asked to find the morality of each solution and were given the moles of the soul Ute and a value total volume. So it&#x27;s training with a were given 0.754 moles of potassium nitrate this K and R three and were given 225 middle leaders As our William, you have to first change this into leaders as the equation we used to find polarity. Ah uses leaders instead of middle leaders. So I&#x27;m gonna divide uhm the divide 225,005,000 to get 0.225 liters as there are 1000 milliliters and one leader. So now that I have the proper units, I have moles and have leaders for my, um volume. I can use the equation C equals and Overbey. So is his concentration equals moles overvalue to find the concentration. So I have moles so is equal to 0.754 moles divided by 0.22 five leaders and this is equal to three point 35 bowlers not is the answer for part A Now for B were given 0.105 molds of calcium chloride and 10.2 milliliters which we have Teoh convert to leaders. So divide 10.2 by 1000 and we get 0.0 102 leaders for our volume. So now we can sub in our mold and our volume to flying concentration. So this is equal to 0.1 05 moles of CCL two, which is the sole Butte fight it by 0.1 02 leaders And this gives us came polarity of 1.3 after the round and that is our polarity with solution. Now, for part C, we&#x27;re given 3.15 moles, uh, sodium chloride were any CEO and were given five leaders for our volume. Um, this is already in leaders, so we don&#x27;t have to do any conversions and we could go right ahead to something in our values into our equation. C equals and Overbey. So this is equal to three wait 15 moles of any seal divided by five 0.0 leaders a solution, and this is equal to zero point 630 molars of solution. And but that is our answer for part C? No. Over party. We have 0.499 moles of sodium bromide and 100 milliliters of solution. So the similar leaders. So you&#x27;re gonna convert still leaders 0.1 leaders. Now we can use our vision. He was an over be again. Nous is equal to zero 0.499 Moles, uh, and a beat are divided by 0.1 Leaders of solution and so similarity of our solution is equal to 4.99 molars.

Nadia Lara · Answer

and this problem. We&#x27;re asked to calculate moles of Salyut for a variety of different solutions. In this first question, we are given a volume of a 0.25250 molar solution. So we have the volume, we have the concentration of the polarity. And so what we&#x27;re being asked to find is the moles of solitude. And if we look at this equation, the way we finals of Salyut is we can multiply the volume by the concentration. So we&#x27;re gonna do that. Notice that the volume, recipe and leaders. So our first step is to change 600 milliliters, two leaders we&#x27;re gonna divide by 1000. So this 600 millilitres is actually 0.600 leaders. So will multiply 0.600 leaders by the concentration, which is 0.250 Moeller. But I&#x27;m gonna write it as moles per leader. That way we can see very clearly that thes units we&#x27;re gonna cancel. We&#x27;re gonna be left with units of moles and that will be 0.150 Moles of the Salyut, which is a strong team. Perlite, in part, really have a similar situation But this time, what they&#x27;re giving us is but Mullah House were given the concentration in units of morality. So we had to use a different equation. But the idea is the same. To find the moles of Saul. You were going to multiply kilograms of solvent by mole LZ. Um, similar situation where were given, Gramps instead of kilograms. So we&#x27;re going to start by changing this two kilograms, Seward will divide by 1000 and gets Europe 10864 kilograms. And when we multiply that times of concentration, um, we&#x27;ll set it up as your point through 864 kilograms. Bye. Well, concentration again. Instead of writing it with units of em, I&#x27;m gonna write it with units of Excuse me malls. You know what&#x27;s wrong with you? I read it with units of Moors for every kilogram. I&#x27;m gonna set right malls for every one looker. And will you notice again? My kilograms cancel. And now what that will give me is 0.156 malls. You can also read it and scientific notation one point 562 instant negative too. And this smalls of the Salyut was his moves of Casey. There&#x27;s been a monk moose, and now, lastly in part. See, this was a little bit different. I can use this formula. There&#x27;s a lot of different ways to kind of work with these percentages were given a total mass. It&#x27;s this were given a total nous. That&#x27;s that piece, and we&#x27;re told that 6.45% of fraction of that mass is the Salyut glucose. So if we need moles of solid oot clearly because we&#x27;re given Mass, we&#x27;re gonna have to do some Master Mel&#x27;s conversion. But first, let&#x27;s find out how much of that 1 24 is glucose. So the first thing we&#x27;re gonna do is we&#x27;re gonna take the 1 20 for total grams and we&#x27;re gonna multiply that by point zero 645 That&#x27;s the percentage converted into a decimal. So it would take the total times the percent. What will get is the component has component in this case is glucose. So that 1 24 is 7.998 grams of glucose, which has, um, the formula si six age 12 06 Now I&#x27;m not quite done because what I was asked if I was malls of Saul. You and I have massive salyut, uh, to change Master Mel&#x27;s. We need the molar mass. You can use your periodic table and find that glucose has the molar mass has a molar mass of 180 0.2 grams for a removal. So we&#x27;ll do this next up as 7.998 Gramps glucose divided by the molar mess. 180.2 grams for everyone. No. And find that this is equal to 0.0 four for four malls of glucose. Um, again written and scientific notation 4.44 I&#x27;m sensing negative second malls.

Nadia Lara · Answer

we&#x27;re asked to calculate most of Saul you each of these questions so that it helps to remember that polarity abbreviated with capital M represents molds for everyone here. So has this one most solve youth and teach you three everyone leader solutions. I&#x27;m told that I have 100 and 25 milliliters again notice and working units of leader. So I need to change that to be 0.125 bleeders. And now that I have these two, I can multiply them together to find the number of mo we have here put 1 to 5 litres solutions multiplied by the concentration. This will give me 0.0 to five models of value, which is any h c 03 That&#x27;s what South noticed that those units canceled. That&#x27;s the solution. We&#x27;re gonna do the same thing with the second question again. We need to work with leader. So this 0.6500 leaders keep tracking your significant figure. City, sir. Obviously there&#x27;s a solution being multiplied by the concentration and polarity, which represents 2.5 moles of age to us before, for everyone here of solution walks by those two valleys. Together we get 1.6 to 5, except I only have three significant figures. So I will around that to 1.63 mold of age to us before.

Problem

How many liters of each solution do you need to g…

Problem 8 Easy Difficulty

Determine the number of moles of solute in each of these aqueous solutions.
a. 50 $\mathrm{L}$ of 0.10 $\mathrm{MaCl}$
b. 0.25 $\mathrm{L}$ of 3.0 $\mathrm{MC}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$
c. 35 $\mathrm{mL}$ of 12.0 $\mathrm{MCl}$
d. 300 $\mathrm{mL}$ of 0.025 $\mathrm{M} \mathrm{NaOH}$

Answer

a. 5 moles of $\mathrm{NaCl}$
b. 0.75 moles of $\mathrm{C} 6 \mathrm{H} 1206$
c. 0.42 moles of $\mathrm{HCl}$
d. 0.0075 moles of $\mathrm{NaOH}$

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a. 5 moles of $\mathrm{NaCl}$b. 0.75 moles of $\mathrm{C} 6 \mathrm{H} 1206$c. 0.42 moles of $\mathrm{HCl}$d. 0.0075 moles of $\mathrm{NaOH}$

Living by Chemistry

Theodore D.

Stephanie C.

Nadia L.

Jake R.

Liquids - Intro

Comparison Of Gases Liquids And Solids

Angelica M. StacyLiving by Chemistry

Theodore D.

Stephanie C.

Nadia L.

Jake R.

a. 5 moles of $\mathrm{NaCl}$
b. 0.75 moles of $\mathrm{C} 6 \mathrm{H} 1206$
c. 0.42 moles of $\mathrm{HCl}$
d. 0.0075 moles of $\mathrm{NaOH}$

Angelica M. Stacy

Living by Chemistry