00:01
So now we'll work on problem from chapter 8.
00:08
In this problem, we're asked to determine the number of valence electrons in an atom of each element, which element do expect to lose electrons and their chemical reactions in which do you expect to gain.
00:24
So the first element that we're given here is aluminum.
00:32
And so we see that aluminum is third in this 3p row, so it should have three valence electrons.
00:44
And in a chemical reaction, we would expect it to lose.
00:50
So a lot of times the elements in a chemical reaction will gain or lose so they can have noble gas configuration.
00:59
So since aluminum has only three valence electrons, it's much easier for it to lose electrons than it is to gain electrons to gain noble gas configuration.
01:11
The second element that we're asked to look at is tin.
01:17
Now, tin has s, d, and p elements, but the d electrons will not be considered valence electrons because they have a lower end value, so we're only going to look for the ones that have the n value, the highest end value.
01:38
So tin has two s electrons and two p electrons in this valence orbital.
01:44
So it has three, four electrons.
01:48
And the same as for aluminum, it's right halfway in terms of having, it's halfway between eight, eight and zero...