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Determine the overall orders of the reactions to which the following rate laws apply: (a) rate $=k\left[\mathrm{NO}_{2}\right]^{2}$(b) rate $=k,$ (c) rate $=k\left[\mathrm{H}_{2}\right]\left[\mathrm{Br}_{2}\right]^{\frac{1}{2}},$(d) rate $=$ $k[\mathrm{NO}]^{2}\left[\mathrm{O}_{2}\right]$.

(a) 2 nd order(b) zeroth order(c) $1.5 \mathrm{th}$ order(d) 3 rd order

Chemistry 102

Chapter 6

Chemical Kinetics

Kinetics

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In probability theory, the conditional probability of an event A given that another event B has occurred is defined as the probability of A given B, written as P(A|B). It is a function of the probability of B, the probability of A given B, and the probability of B.

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In chemistry, kinetics is the study of the rates of chemical reactions. The rate of a reaction is the change in concentration of a reactant over time. The rate of reaction is dependent on the concentration of the reactants, temperature, and the activation energy of the reaction.

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Determine the overall orde…

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For each of the following …

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Determine the overall reac…

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OBJECTIVE. Identify the re…

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For each of these rate law…

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For each of the rate laws …

the overall order. It's simply the sum of the exponents in a great law. So, for example, if we have the rate law of rate is equal Teoh Ari constant k times a concentration of a to the end kinds of concentration of be to the end our overall rate is equal to him, Plus in So given this information, we can then work through the problems. So problem A were given that the rate is equal to K has a concentration of, you know, to squared. So there's only who won exponents here. So the answer of the overall order is simply second order or a problem be were given that the rate is equal to okay. So in this rate law, we have no exponents. So therefore, our reaction is zero order problem. See, our rate is k times a concentration of h two times the concentration of we are to to go in half. So the exponents of our concentration of H two is one and the exponents of our concentration of br to is loin half. So the overall order is one point five We're problem d we're given the rate is equal to okay time the concentration off, you know, squared times the concentration off. Oh, to adding together the exponents, The exponents, where the concentration of you know is to in the exponents for the concentration of 02 is one. So our overall order is third order.

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