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Hello, we're going to talk about assigning oxidation numbers.
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I've written a very, very abbreviated set of rules.
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For a pure element, the oxidation number is always zero.
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The monotomic ions, the oxidation number is the charge.
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When fluorine is combined, it's always negative 1.
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When oxygen is combined, it's mostly negative 2, unless with fluorine, then it's positive.
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Or a peroxide, it's negative one, or a superoxide, it's negative one -half.
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Let's see here.
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And next we have chlorine, bromine, and iodine.
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They're negative one, except when they're with oxygen or fluorine.
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Hydrogen is usually a plus one, except when it's a metal hydride, and it's negative one.
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The algebraic sum of a molecule or formula unit of a compound is zero.
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And the algebraic sum of an ion is the ion.
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Let's practice.
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I'm going to go to a little darker color.
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For our first substance, we're going to look at b .r .o .3 with a negative one charge.
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So we're going to figure out the charge for bromine and the charge for oxygen.
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Oxygen is negative 2 because it's negative 2 just because we know that it is not a peroxide or superoxide and it's going to be a negative 2.
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We have an overall charge on our ion of a negative 1.
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So this has to be a plus 5 because if i add these two numbers, i get a negative 1, which is the charge of the ion.
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So on these two substances, bromine is a plus 5.
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Oxygen is a minus 2.
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Let's do another.
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Next we have c2, 04 with a 2 minus 2.
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Charge.
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So i have c and o.
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Again, oxygen is going to be a negative 2.
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And if i take negative 2 times 4, i get a negative 8.
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What does the charge on our carbon have to be in order to have a negative 2 as the algebraic sum of these two substances? it needs to be plus 6...