Question
Determine the oxidation state of Xe and give the VSEPR structure for each compound.a. $\mathrm{XeF}_{2}$b. $\mathrm{XeF}_{6}$c. XeOF $_{4}$
Step 1
a. XeFâ‚‚ - Fluorine (F) has an oxidation state of -1. - Let the oxidation state of Xe be x. - The equation for the compound is: x + 2(-1) = 0. - Solving for x gives: x - 2 = 0, so x = +2. - The oxidation state of Xe in XeFâ‚‚ is +2. b. XeF₆ - Fluorine (F) has an Show more…
Show all steps
Your feedback will help us improve your experience
Amy Jiang and 81 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Draw the Lewis structures. Use VSEPR theory to predict the probable geometric structures of the molecules. Find the oxidation state of the Xe atom for each molecule. (a) XeO2F2 (b) XeO3F2 (c) XeF4O
What is the oxidation state of the noble gas in each of the following? You may wish to review the chapter on chemical bonding and molecular geometry. (a) $\mathrm{XeO}_{2} \mathrm{F}_{2}$ (b) $\mathrm{KrF}_{2}$ (c) $\mathrm{XeF}_{3}+$ (d) $\mathrm{XeO}_{6}^{4-}$ (e) $\mathrm{XeO}_{3}$
Determine the oxidation state and coordination number of the metal ion in each complexion. $$ \begin{array}{ll}{\text { a. }\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Br}\right]^{2+}} & {\text { b. }\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}} \\ {\text { c. }\left[\mathrm{Co}(\mathrm{ox})_{3}\right]^{4-}} & {\text { d. }\left[\mathrm{PdCl}_{4}\right]^{2-}}\end{array} $$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD