Then we have:
$$
\frac{x^{2}-x-12}{x^{2}+2 x-3} \cdot \frac{P(x)}{x^{2}-2 x-8}=1
$$
Now, we want to find P(x) such that the equation above holds true. To do this, we can multiply both sides of the equation by the denominators of the fractions:
$$
(x^{2}-x-12)
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