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Determine the pressure of the gas in the syringe shown in Figure 9.13 when its volume is 12.5 mL, using:

(a) the appropriate graph(b) Boyle’s law

a) 15.38 $\mathrm{psi}$b) 15.6 $\mathrm{psi}$

01:48

Aadit S.

Chemistry 101

Chapter 9

Gases

Virgilio L.

September 28, 2020

in addition to the data found in figure 5, what other information do we need to find the mass of the sample of air used to determine the graph

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So what we're taking a look at here is Boyle's law, and it says that pressure in vastly proportional to volume. So we can also represent that as p one B one is equal to P to be to so what we have is a diagram that is one of a P Busses temperature. And so from our graph, the value of one overpay coordinate for V that is equal to 12.5 is 0.65 Pierre sides the minus one So that full one overpay, they could see their 0.65 Well, we determined P it's equal to 1/0 0.65 and P is equal to 15 point 38 PSC. That is Thebes. Pressure of the gas at 12.5 mil volume. So in the next pop to this podcast we re arrange, that equation that we saw here on will rearrange that to P two is equal to P one. Be one over B two. So we compare the power our coordinates from the graph we substitute in 19.5 p. S I for P 1 10 mil for V one and 12.5 mil for feet, too, to calculate p two. So I'll write that down. P two is equal to 19.5 PSC multiplied by 10 mL, divided by 12.5 mL. So you can see our milliliters units canceled their my left with units of PSC, which is good because we're after a pressure. We get 15.6 p. S I.

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