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Welcome to numerid.
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In the current problem we are given lambda is equals to 3 and we have to find the probabilities for 6, 7 and 8.
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So for probability of x is e to the power minus lambda into lambda to the power x by x factorial.
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Over here lambda is 3.
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So e to the power minus 3 into 3 to the power x by x factorial.
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So for probability of 6 we have e to the power minus 3 into 3 to the power 6 by 6 factorial.
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And if we use a calculator, we will arrive at the value 0 .050409.
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Following the same steps, we will receive the value of p6, a p7, which is e to the power minus 3 into 3 to the power 7 by 7 factor.
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Which again on simplification will become this and p8 is this now in when we are doing it on calculator it is pretty much difficult to each time punch in these numbers right so there must be some easier way to do this so i will show you how can we achieve that so there is a recursion relation of or rather i can say instead of this let us take p of x plus 1 divided by p of x...