00:01
We want to find the probability of each outcome when a bias to die is rolled.
00:07
So let p of 1 equal to x, where p of 1 is the probability that we will roll and get 1.
00:15
We know that 1 is equally likely to appear as 3, 5, and 6.
00:20
So x is equal to p of 1, which is equal to p of 3, which is equal to p of 5, and which is equal to p of 6.
00:28
We also know two or three is three times more likely to occur than each of the other outcomes.
00:36
So p, two, or four, is equal to p of two plus p of four, since rolling a two or rolling a four is independent from each other.
00:51
And that's equal to three times p of one plus p of three, plus p of three, plus p of five, plus p of six.
01:03
This is three times more likely to happen that either of these outcomes...