00:01
Hi everyone here we have to calculate product of inertia of shaded area with respect to x -axis and y -axis.
00:11
So i x -y we have to calculate then using the parallel axis theorem we have to find product of inertia with respect to central and also find i x -by -dase given y -square is equal to x now we will consider the element, differential element of thickness dx at a distance x and y.
01:03
Its centroid will be here.
01:16
So area of the differential element is y into d x from equation 1 .y is root of x t x having centroid x comma y by 2.
01:45
And parallel to y -axis.
02:02
Product of inertia of this element will be 5 plus area into central x -y -by -wire.
02:20
So this is 0, x -key -power half, dx, central -x into y -half.
02:33
And value of y, we know, x -key -power -half.
02:49
So you will get d ixy to be half x square d x to find the product of inertia of the set it area we have to integrate it...