00:01
So at the power plant, the power of 100 kilowatt is delivered at a voltage of 12 ,000 volts.
00:14
So from these two informations, we can find the initial current using equation 18 .9a.
00:23
So we know that power is current times voltage.
00:28
So current is equal to power over voltage and substituting these two we get the current to be 8 .333 ampere.
00:41
Make sure you convert the kilowatts into watts before calculating the ratio.
00:47
Then we have a step up transformer which steps up the voltage by a factor of 20.
00:55
And since the current and voltage are inversely proportional, so the current is stepped down by a factor of 20, which means that, so let me just write the equation again.
01:16
So we know that is over ip is equal to np over ns, and we also know that vs over vp is equal to ns over ns, and we also know that v .p is equal to ns over ns over n.
01:30
Now v s over vp is given to be 20 which means that n s over np is also equal to 20 and that means that i s over ip will be equal to np over ns and hence 1 over 20 and therefore is s will be equal to ip times 1 over 20 and ip is the one that we found here so this is this is ip and this was obviously vp and therefore we substitute this value over here and find is to be 0 .4167 ampere...