Question
Determine the relative phase relationship of the two waves $$\begin{array}{l}v_{1}(t)=10 \cos \left(377 t-30^{\circ}\right) \mathrm{V} \\v_{2}(t)=10 \cos \left(377 t+90^{\circ}\right) \mathrm{V}\end{array}$$
Step 1
The phase angle of the first wave, $v_{1}(t)$, is $-30^{\circ}$ and the phase angle of the second wave, $v_{2}(t)$, is $90^{\circ}$. Show more…
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Determine the relative phase relationship of the two waves $$\begin{array}{l} v_{1}(t)=10 \cos \left(377 t-30^{\circ}\right) \mathrm{V} \\ v_{2}(t)=10 \cos \left(377 t+90^{\circ}\right) \mathrm{V} \end{array}$$
Given the following voltage and current: $$\begin{array}{l}i(t)=5 \sin \left(377 t-20^{\circ}\right) \mathrm{V} \\v(t)=10 \cos \left(377 t+30^{\circ}\right) \mathrm{V}\end{array}$$ Determine the phase relationship between $i(t)$ and $v(t)$.
Q4// i) Determine the relative phase relationship of the two waves 01(t) = 10 cos (377t - 309) V 02(t) = -5 cos (385t + 909) V. ii) Given i(t) = 5 cos (400t - 1209) A, determine the period of the current and the frequency in Hertz.
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