We have two forces acting on the member AB, one is the force P = 9 kip and the other is the force due to the weight of the member itself. We can write this as:
\[2F_{60} - P = 0\]
Solving for \(F_{60}\), we get:
\[F_{60} = \frac{P}{2} = \frac{9}{2} = 4.5 \text{
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