The sum of the forces in the x-direction should be equal to zero. This gives us the equation:
\[ \Sigma F_x = 0 = -400 \cos(30^\circ) + F_{B_x} + 300 \cos(60^\circ) - F_{C_x} \]
Solving this equation, we find that \( F_{B_x} = 496 \, \text{lb} \).
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