00:01
Okay, we're going to solve this system by substitution, which means we need to get a variable by itself.
00:08
So i'm going to look at this bottom one, and i'm just going to subtract 4.
00:14
So we'll have y equals 6 minus 4x.
00:21
So i'm going to substitute that into our top equation.
00:25
I'm going to have 1 3rd x minus 1 1 1ā2, but instead of using y, i'm going to say 6 minus 4x, equals negative 2 thirds.
00:40
So let's distribute our 1 1 1 3x minus 3 plus 2x equals negative 2 thirds.
00:53
And so here i'm going to pause and i'm going to multiply everything by 3 to get rid of our fraction.
01:01
So 1 3 times 3 is just 1.
01:05
3 times 3 is 9, 2 times 3 is 6, and negative 2 thirds times 3 is just negative 2.
01:14
So it cancels out really nicely, and so let's combine our like terms, 7x minus 9 equals negative 2...