00:01
In this question, we are being asked to find the sum of a geometric series if it converges.
00:09
In order to do that, we need to use our formula.
00:13
The sum of an infinite geometric series is equal to a sub 1, or my first term in the series, divided by 1 minus the ratio, or what i multiply by each term to produce the next number.
00:30
Let's look at our two initial values.
00:34
We have 5 to the third power over 3, which will be my a1 term, minus 5 to the 5th power over 3 to the 4th power.
00:49
My ratio will be equal to what i multiply by this first term to produce the second term.
00:59
Notice that that minus has now become a negative 5 to the 5.
01:04
Over 3 to the 4th.
01:07
If i look at my numerator, i know that 5 to the cubed power times 5 squared would give me two more fives to produce 5 to the 5th power.
01:23
My ratio, again negative, will have a numerator of 25 or 5 squared.
01:33
My denominator, on the other hand, goes from 3 to 3 to the 4th power, which means i would need to multiply by three to the third power...