00:01
Hi guys, in this problem we are given that is a showing density function of x and y such that f of x and y equals c x y where x where x is between 0 and 3 and y between 0 and x and otherwise okay so we have to find the value of of c such that the given density is a proper density and we know that the integration over x and y for f of x and y equals 1 so integration for x from 0 to 3 then integration of y from 0 to x for c x y okay d y x equals 1 so this integration integration from 0 to 3 for cx then y squared over 2 then we substitute by its limits x and 0 d x so this equals to c over 2 integration from 0 to 3 for execute the x okay, so this equals to c over 2 times x power 4 over 4 and then substitute by elements of x, which is 3 and 0.
01:45
So this equals to c over 2 times 3 power 4 over 4 equals 1.
01:54
And hence c equals 8 over 81.
02:03
Okay.
02:05
Now the preferred density function is 8 over 81 xy between the given limits.
02:11
So now we have to find the covariance and correlation between x and y.
02:19
So let's, the first step we need to do is to find the mean of x, which is integration.
02:26
From 0 to 3, then integration from 0 to x, 4 ,8x times f of x, which is 8 over 81, xy, d -y, d -y, d -x.
02:45
Okay, so calculating this integration, we get 8, 4, sorry, it's 4 over 81 times the integration from 0 to 3, 4, 4 ,000, times the integration from 0 to 3, 4x.
02:59
Power 4 the x.
03:02
Okay, so this is 4 over 81 times x power 5 over 5...