00:03
In part a of problem 80, we are looking for the resultant force.
00:08
We are given each of the components, i, j, and k components.
00:14
To find the resultant force, we can set it equal to the square root of the sum of the squares of each component.
00:39
So plugging in for the x direction, we have 320 newton squared, plus the y direction of 400 newtons squared, plus the z direction.
00:52
Of negative 250 newtons squared.
01:00
And this comes out to 570 newtons for the resultant force.
01:06
Now in part b, we are looking for each component of the angle of the resultant force.
01:14
So looking at the x component, we can find it by taking the cosine of theta and setting it equal to the x component of the force over the resultant force...