The outside diameter of the tube is \( D_{out} = 50 \, \text{mm} \) and the wall thickness is \( t = 5 \, \text{mm} \).
The inside diameter \( D_{in} \) can be calculated as:
\[
D_{in} = D_{out} - 2t = 50 \, \text{mm} - 2 \times 5 \, \text{mm} = 40 \,
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