00:01
Okay, for this problem, we have a plate that has four different forces acting on it.
00:05
Force 1, force 2, force 3, and force 4, and it actually gives us the magnitudes and angles for each of these.
00:11
It actually doesn't give us the actual angles, but it tells us that force 1 and force 2 form 3 or 4 or 5 triangles with the x and y axis.
00:20
So using these, we have to actually find the result in force vector and show that the result in force is 0.
00:26
So we can do this by determining the x and y components and summing each of them individually.
00:31
To see that they both add up to zero.
00:34
So let's start with the horizontal component or the x component.
00:38
Because we have all the magnitudes and we can determine the components based in these 3 ,4 ,5 triangles, we can look at each of these triangles individually.
00:50
So this one right here is the triangle that the f -force 1 forms with the y and x axis.
00:56
And this triangle on the right side is the one force 2.
01:01
Forms with x and y axis.
01:04
So we'll start with force one.
01:05
So for the horizontal component, we're going to be looking at, we're going to be using right angle trig, so sokatoa, right, to determine what the purely horizontal component is.
01:16
So here, because we need to find the horizontal side or horizontal component, we use cosine in sokatoa, which is adjacent over hypotenuse.
01:29
So here it's going to be eight, what does the this in blue.
01:33
It'll be 8 kiloons times 4 over 5.
01:37
I'm moving on to force 2 plus.
01:41
And here it's going to be sokatoa once again, but it'll be 3 over 5.
01:45
So it would be 6 kilonutons, because that's magnitude of f2, times 3 over 5...