The impedance of the inductor is given by $j\omega L$ and the impedance of the capacitor is given by $1/j\omega C$. Here, $\omega = 240$ rad/s, $L = 2$ mH, and $C = 12$ ÎĽF. So, we have:
\[
Z_L = j\omega L = j240 \times 2 \times 10^{-3} = j0.48 \,
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