Question
Determine where the graph of the function is concave upward and where it is concave downward.$$g(x)=x+\frac{1}{x^{2}}$$
Step 1
The derivative of $x$ is $1$ and the derivative of $\frac{1}{x^{2}}$ is $-\frac{2}{x^{3}}$. So, the first derivative of the function $g(x)$ is $g'(x) = 1 - \frac{2}{x^{3}}$. Show more…
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